(2x^2+7x+3)/(2x^2-7x-4)

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Solution for (2x^2+7x+3)/(2x^2-7x-4) equation:


D( x )

2*x^2-(7*x)-4 = 0

2*x^2-(7*x)-4 = 0

2*x^2-(7*x)-4 = 0

2*x^2-7*x-4 = 0

2*x^2-7*x-4 = 0

DELTA = (-7)^2-(-4*2*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)+7)/(2*2) or x = (7-81^(1/2))/(2*2)

x = 4 or x = -1/2

x in (-oo:-1/2) U (-1/2:4) U (4:+oo)

(2*x^2+7*x+3)/(2*x^2-(7*x)-4) = 0

(2*x^2+7*x+3)/(2*x^2-7*x-4) = 0

2*x^2+7*x+3 = 0

2*x^2+7*x+3 = 0

DELTA = 7^2-(2*3*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)-7)/(2*2) or x = (-25^(1/2)-7)/(2*2)

x = -1/2 or x = -3

(x+3)*(x+1/2) = 0

2*x^2-7*x-4 = 0

2*x^2-7*x-4 = 0

DELTA = (-7)^2-(-4*2*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)+7)/(2*2) or x = (7-81^(1/2))/(2*2)

x = 4 or x = -1/2

(x+1/2)*(x-4) = 0

((x+3)*(x+1/2))/((x+1/2)*(x-4)) = 0

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x+3 )

x+3 = 0 // - 3

x = -3

x in { -1/2}

x = -3

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